Is it possible to sort a list in a "for in"-loop (Python)

Question

So I have this:

Channel.groups.sort() # Channel.groups is a list of strings

for country in Channel.groups:
    print(country)

But I would like to do something like this:

for country in Channel.groups.sort():
        print(country)

# This results in error: TypeError: 'NoneType' object is not iterable

Is it possible to somehow force Channel.groups.sort() to "execute" before it starts to iterate through the list?

Answer 1

sort() is inplace, meaning it modifies the original list it is called upon and returns None (which is why you are getting the error 'NoneType' object is not iterable).

You will need to use something that leaves the original list intact and returns a new, sorted list, like sorted():

for country in sorted(Channel.groups)