append to list the result of a thread

Question

this is my code:

import threading

def worker(num):
    """thread worker function"""
    print '{Worker: %s}' % num
    return

threads = []
for i in range(5):
    t = threading.Thread(target=worker, args=(i,))
    threads.append(t)
    t.start()
print(threads)

and this is the result from above code:

{Worker: 0}
{Worker: 1}
{Worker: 2}
{Worker: 3}
{Worker: 4}
[<Thread(Thread-1, stopped 17204)>, <Thread(Thread-2, stopped 852)>, <Thread(Thread-3, stopped 17092)>, <Thread(Thread-4, stopped 10632)>, <Thread(Thread-5, stopped 2396)>]

how can i append those results to list and create a list something like this:

[[{Worker: 0}],[{Worker: 1}],[{Worker: 2}],[{Worker: 3}],[{Worker: 4}]]

---

edited: in reality my def contain a request REST method and it consume some seconds and after some trying i found thread not wait to get result and not fill array list, then i reform my code into a string variable to simulate for you, in this situation i put a time.sleep(1) in first line of def and then run thread, it's have a empty list.... i less sleep time to 0.001 till get result and thread work and array have populated.

import threading

def worker(txt):
    """thread worker function"""
    if txt != '[{}]':
        time.sleep(0.01) # this time has empty result till replace with 0.001 or lesser
        lst.append(['{Worker: %s}' % txt])
        # time.sleep(5)
        return


xx = ['abc','def','ghi','jkl','mno','pqr','stw','xyz']

threads, lst = [], []
for i in xx:
    t = threading.Thread(target=worker, args=(i,))
    threads.append(t)
    t.start()
    # t.join()
print(lst) #[['{Worker: abc}'], ['{Worker: jkl}'], ['{Worker: ghi}'], ['{Worker: def}']] for 0.001 sleep time
# print(threads)

Answer 1

Do you mean something like this?

import threading

def worker(num):
    """thread worker function"""
    lst.append(['{Worker: %s}' % num])
    return

threads, lst = [], []
for i in range(5):
    t = threading.Thread(target=worker, args=(i,))
    threads.append(t)
    t.start()
print(lst)
#print(threads)

# [['{Worker: 0}'], ['{Worker: 1}'], ['{Worker: 2}'], ['{Worker: 3}'], ['{Worker: 4}']]