Convert a list of tuples into a list of dict

Question

I have a list of tuple:

[('Lebron James', datetime.date(2017, 12, 23), 500),
 ('Julie Peralta', datetime.date(2017, 12, 13), 1500),
 ('Reynaldo Pahay', datetime.date(2017, 12, 11), 2500)]

I want to convert it into a list of dictionary:

[{'Name': 'Lebron James', 'date': datetime.date(2017, 12, 23), 'penalty': 500},
 {'Name': 'Julie Peralta', 'date': datetime.date(2017, 12, 13), 'penalty': 1500},
 {'Name': 'Reynaldo Pahay', 'date': datetime.date(2017, 12, 11), 'penalty': 2500}]

What's the best and efficient way to do it?

Answer 1

You can make use of zip function.

def get_list_of_dict(keys, list_of_tuples):
    """
    This function will accept keys and list_of_tuples as args and return list of dicts
    """
    list_of_dict = [
        dict(zip(keys, values))
        for values in list_of_tuples
    ]
    return list_of_dict

DEMO

>>> import datetime
>>> 
>>> keys = ("name", "date", "penalty")
>>> 
>>> my_list_of_tuples = [
...     (
...         "Lebron James",
...         datetime.date(2017, 12, 23),
...         500,
...     ),
...     (
...         "Julie Peralta",
...         datetime.date(2017, 12, 13),
...         1500,
...     ),
...     (
...         "Reynaldo Pahay",
...         datetime.date(2017, 12, 11),
...         2500,
...     ),
... ]
>>> 
>>> get_list_of_dict(keys, my_list_of_tuples)
[{'name': 'Lebron James', 'date': datetime.date(2017, 12, 23), 'penalty': 500}, {'name': 'Julie Peralta', 'date': datetime.date(2017, 12, 13), 'penalty': 1500}, {'name': 'Reynaldo Pahay', 'date': datetime.date(2017, 12, 11), 'penalty': 2500}]
>>>