How to get user-defined methods name?

Question

I'm trying to get all the user-defined methods name from a class, ex:

class MyClass:
    def __init__(self, param1, param2):
        pass

    def one_method(self):
        pass

    def __repr__(self):
        pass

    def __str__(self):
        pass

    def __my_method_no_2(self, param2):
        pass

    def _my_method_no_3(self):
        pass

so far I have come to the following approach:

import inspect 

[name for name, _ in inspect.getmembers(MyClass, inspect.isroutine)
 if name not in {'__init_subclass__', '__subclasshook__'} and 
 getattr(MyClass, name).__qualname__.startswith(MyClass.__name__)]

output:

['_MyClass__my_method_no_2',
 '__init__',
 '__repr__',
 '__str__',
 '_my_method_no_3',
 'one_method']

this is the expected output, but this looks "ugly" and not even sure if is the right approach

Answer 1

Got the idea from here, but using __dict__ instead of dir.

Every python objects has a __dict__ attribute containing names of all attributes. Relevant docs here

The idea is: get a list of attributes from __dict__ and filter out everything non-callable

[attr for attr in  MyClass.__dict__ if callable(getattr(MyClass, attr))]

Matches with your output

Answer 2

In Python 3.x, you can use dir without inspect or any external libraries:

method_list = [func for func in dir(Foo) if callable(getattr(Foo, func))]

To handle every method that you newly define in your class and override in your class, Try this:

class MyClass:
    li = []
    def __init__(self, param1, param2):
        pass

    def one_method(self):
        pass

    def __repr__(self):
        pass

    def __str__(self):
        pass

    def __my_method_no_2(self, param2):
        pass

    def _my_method_no_3(self):
        pass


print([func for func in dir(MyClass) if callable(getattr(MyClass, func)) and func in MyClass.__dict__])

Outputs:

['_MyClass__my_method_no_2', '__init__', '__repr__', '__str__', '_my_method_no_3', 'one_method']