How to return assciative arrays from zsh function?
I tried:
creatAARR() {
declare -A AARR=([k1]=2 [k2]=4)
return $AARR
}
creatAARR
But i get error:
creatAARR:return:2: too many arguments
What is the right way?
EDIT: I captured output to standard output, like how @chepner suggests, but the new variable doesn't seem to behave like an associative array:
creatAARR() {
declare -A AARR=([k1]=2 [k2]=4)
echo "$AARR"
}
declare -A VALL
NEW_ARR=$(creatAARR)
echo "$NEW_ARR" # 2 4
echo "k1: $NEW_ARR[k1]" # prints just k1:
return
Any suggestions?
return accepts only an integer and sets the exit status of the function.
Shell commands cannot actually return values. If you want pass information to the caller of your function, you have a couple of options available to you:
print your return value, but this then relies on you to properly format your output and for the caller to correctly parse it. For associative arrays, there are so many ways that this can go wrong; I wouldn’t recommend doing this.$REPLY to a scalar value or $reply to an array. Unfortunately, there is no convention for passing associative arrays. You could, of course, put your key-value pairs simply as elements in the non-associative array $reply and then let the caller cast it to or wrap it in an associative array, but this would break the convention and thus might violate your caller's expectations.This last approach you can use as follows:
% creatAARR() {
# Restrict $name to function scope.
local name=$1
# Delete $1, so $@ becomes the other args.
shift
# Assign elements to array.
set -A "$name" "$@"
}
% typeset -A AARR=() # Declare assoc. array
% creatAARR AARR k1 2 k2 4
% typeset -p1 AARR # Print details
typeset -A AARR=(
[k1]=2
[k2]=4
)
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