I have an XSLT like this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xalan="http://xml.apache.org/xalan">
<xsl:variable name="fooDocument" select="document('fooDocument.xml')"/>
<xsl:template match="/">
<xsl:apply-templates select="$fooDocument//*"/>
</xsl:template>
<xsl:template match="nodeInFooDocument">
<xsl:variable name="valueFromSource" select="//someSourceElement"/>
</xsl:template>
</xsl:transform>
In the second template, which matches nodes in the fooDocument.xml which is loaded with document(), I want to access nodes in the XML source the transformation is executed upon. This does not work with //someSourceElement, because apparently, XPath executes this path in the context of fooDocument.
A first workaround that comes to mind is this:
...
<!-- global variable -->
<xsl:variable name="root" select="/"/>
...
<!-- in the template -->
<xsl:variable name="valueFromSource" select="$root//someSourceElement"/>
...
But I cannot use this workaround, because actually, my variable is selected like this:
<xsl:variable name="valueFromSource" select="xalan:evaluate($someXPathString)"/>
$someXPathString is not crafted in the XSLT file, but loaded from fooDocument (and contains an absolute path like the one used above). Still, I need to somehow change the XPath context back to the XML source. A very hacky workaround I found is this:
<xsl:for-each select="$root[1]">
<xsl:variable name="valueFromSource" select="xalan:evaluate($someXPathString)"/>
</xsl:for-each>
The (useless) for-each loop changes the context back to the main XML source, thus the XPath evaluates correctly. But obviously, this is not an acceptable solution.
Is there a way to do this right, or can someone suggest a better workaround?
Even if you think your attempt with a for-each select="$root" to change the context document is not acceptable this is the right approach. So use that, there is no other way.
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