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Why doesn't xmlstarlet select all nodes?

Consider this example from w3schools:

<?xml version="1.0" encoding="ISO-8859-1"?>

<bookstore>

<book category="COOKING">
  <title lang="en">Everyday Italian</title>
  <author>Giada De Laurentiis</author>
  <year>2005</year>
  <price>30.00</price>
</book>

<book category="CHILDREN">
  <title lang="en">Harry Potter</title>
  <author>J K. Rowling</author>
  <year>2005</year>
  <price>29.99</price>
</book>

<book category="WEB">
  <title lang="en">XQuery Kick Start</title>
  <author>James McGovern</author>
  <author>Per Bothner</author>
  <author>Kurt Cagle</author>
  <author>James Linn</author>
  <author>Vaidyanathan Nagarajan</author>
  <year>2003</year>
  <price>49.99</price>
</book>

<book category="WEB">
  <title lang="en">Learning XML</title>
  <author>Erik T. Ray</author>
  <year>2003</year>
  <price>39.95</price>
</book>

</bookstore>

xmlstarlet sel -t -v "//@category" books.xml

returns only COOKING. How to get all attributes named category?

BONUS question: how do I evaluate XPath queries against an XML file without opening it in an editor nor program (I want a quick tool). The issue is that loading the huge file into memory crashes the editor. Don't tell me that eXist is my best bet?

like image 460
simpatico Avatar asked Dec 09 '25 02:12

simpatico


1 Answers

Is this what you need?

xml sel -t -m "//@category" -v "." -o " " books.xml

or to separate the results on each line

xml sel -t -m "//@category" -v "." -n books.xml

Update

You're right, your XPath was good, you just need different parameters.

like image 196
cordsen Avatar answered Dec 11 '25 23:12

cordsen



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