I'm currently looking at C++ code that uses ::delete to delete a pointer.
A meaningless example of this is:
void DoWork(ExampleClass* ptr)
{
::delete ptr;
}
What is the purpose of using the delete keyword in this way?
In some cases, the operator delete might be redefined -actually overloaded- (for example, your Class might define it and also define operator new). By coding ::delete you say that you are using the standard, "predefined", deletion operator.
A typical use case for redefining both operator new and operator delete in some Class: you want to keep a hidden global set of all pointers created by your Class::operator new and deleted by your Class::operator delete. But the implementation of your delete will remove that pointer from the global set before calling the global ::delete
This is using the delete expression, but with the optional :: prefix.
Syntax
::(optional)deleteexpression (1)...
Destroys object(s) previously allocated by the
newexpression and releases obtained memory area.
Using the :: prefix will affect lookup:
The deallocation function's name is looked up in the scope of the dynamic type of the object pointed to by expression, which means class-specific deallocation functions, if present, are found before the global ones.
If
::is present in the delete expression, only the global namespace is examined by this lookup.
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