If I instantiate a lambda somewhere (and the compiler doesn't inline it), I can find a string showing where the lambda is located in my c++ code like this:
... ?AV<lambda_1>@?0??MyFunction@MyScopedClass@MyNamespace@@SAXXZ@ ...
I don't want this information in the executable, as it could give away important names of classes and functions.
All kinds of output debug information are turned off. If I use a normal function instead, the final executable doesn't have this information, so manually converting all lambdas into normal functions would "fix it". But what's the best way to handle this? Can we tell the compiler to transform lambdas into normal functions?
UPDATE: I tested with other compilers: g++ and clang. They both leave the same references. I also found another unanswered question about this Gcc - why are lambdas not stripped during release build Please don't come with the "why do you care about a few symbols anyway".
Here's some code you can test with:
#include <iostream>
#include <functional>
class MyUnscopedClass
{
public:
MyUnscopedClass(const std::function<void(int x)>& f) :
f(f)
{
}
std::function<void(int x)> f;
};
namespace MyNamespace
{
class MyScopedClass
{
public:
static void temp1(int x)
{
std::cout << x * (x + 1);
}
static void MyFunction()
{
//MyUnscopedClass obj(temp1); // no symbols
MyUnscopedClass obj([](int x) // ?AV<lambda_1>@?0??MyFunction@MyScopedClass@MyNamespace@@SAXXZ@
{
std::cout << x;
});
obj.f(23);
}
};
}
int main()
{
MyNamespace::MyScopedClass::MyFunction();
}
With the help of @dxiv in the comments, I found the problematic setting.
Configuration Properties > General > C++ Language Standard
can't be, for some reason,
Preview - Features from the Latest C++ Working Draft (std:c++latest)
So I set it to the second most recent one
ISO C++17 Standard (std:c++17)
and I get a random identifier instead.
AV<lambda_f65614ace4683bbc78b79ad57f781b7f>@@
I'm still curious how this identifier is chosen though.
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