im using python 3.7 and i wanted to write a program that takes name of a city and returns the weather forcast . i started my code with :
import re
import urllib.request
#https://www.weather-forecast.com/locations/Tel-Aviv-Yafo/forecasts/latest
city=input("entercity:")
url="https://www.weather-forecast.com/locations/" + city +"/forecasts/latest"
data=urllib.request.urlopen(url).read
data1=data.decode("uf-8")
print(data1)
but when I wanted to read my data i got this error :
File "C:\Users\User\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 503, in _call_chain result = func(*args) File "C:\Users\User\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 649, in http_error_default raise HTTPError(req.full_url, code, msg, hdrs, fp) urllib.error.HTTPError: HTTP Error 404: Not Found Process finished with exit code 1
=> can some one help me and tell what is the problem ? thanks:)
There must be some spelling mistake in the city name you have entered. I tried running the following code
import re
import urllib2
city=input("enter city:")
url="https://www.weather-forecast.com/locations/" + city +"/forecasts/latest"
data=urllib2.urlopen(url).read()
print(data.decode('utf-8'))
It works properly when i input
enter city:'newyork'
While the same code throws HTTPError: HTTP Error 404: Not Found error if the input is
enter city:'newyolk'
You can solve this by using a try-except statement
city=input("enter city:")
url="https://www.weather-forecast.com/locations/" + city +"/forecasts/latest"
try:
data=urllib2.urlopen(url).read()
print(data.decode('utf-8'))
except:
print('The entered city does not exist.Please enter a valid city name')
Tried with requests library it worked.
import requests
city = input("entercuty:")
url = "https://www.weather-forecast.com/locations/"+city+"/forecasts/latest"
data = requests.get(url)
print(data.status_code)
print(data.text)
Gave city as "Stuttgart".
Status code: 200
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