Using "if all" in python

Question

Why this work

for td in alltd:
    if "style3" in td["class"] or "style4" in td["class"] or "style1" in td["class"]:
        td["class"] = "s1"

and this not?

for td in alltd:
    if all(x in td["class"] for x in ("style3", "style4", "style1")):
        td["class"] = "s1"

Answer 1

all([x1,x2,...]) is basically the same as x1 and x2 and ..., not x1 or x2 or ...

>>> all([True, True])
True
>>> all([True, False])
False

Use any() instead.

>>> any([True,False])
True