unexpected result in bit shifting operation

Question

I think the answer is straight forward but still I am not getting it.

byte a=5;
int b=10;
int c=a>>2+b>>2;
System.out.print(c);

As a>>2 is 1 and b>>2 is 2, I am expecting output to be 3 but is 0. What's the reason?

Answer 1

It's because of operator precedence.

What you do is the same as

int c=(a>>(2+b))>>2;

You want this :

int c=(a>>2)+(b>>2);