ToCharArray generates two sets of numbers instead of one

Question

Hi I am trying to split a string into an array of chars but for some reason the result is not what I expect.I passed this piece of code threw with the debugger and i gave it the string "34325".When I reach the part of the code that converts the string into an array of chars for some reason I can see two sets of chars in the debugger.I get something like this:

char[0] = 51 '3' char[1] = 52 '4' char[2] = 51 '3' char[3] = 50 '2' char[4] = 53 '5'

When I then convert each element of the char array into an int the first number of is always take : 51 , 52 ,51 , 50 , 53.

My question is how can I correct this so I get 3 , 4 , 3 , 2 , 5? And also from where are this numbers coming from when I use the toCharArray() method : 51 ,52 ,51 ,50 53?

This is my code:

    value = TextBox1.Text;

    char[] numberChars = value.ToCharArray();
    int[] numbers = numberChars.Select(x => Convert.ToInt32(x)).ToArray();

    for( int i = 0; i < numbers.Length; i++ ) {
        TextBox2.Text += numbers[i] + " ";
    }

Answer 1

If I understand your question correctly, you would like to split the string into integer numbers representing the digits, as follows: "34325" becomes new int[] {3,4,3,2,5}.

Change your code as follows to interpret each character that represents a digit as a single-digit number:

 int[] numbers = numberChars.Select(x => ((int)x)-'0').ToArray();

Here is a link to a demo on ideone.

The reason you see numbers 51, 52, and so on is that you see ASCII codes for the corresponding digits.

Answer 2

the "other" sequence you got is the sequence of ascii values ...

have a look at int.Parse(string)