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to_string and convert.str() not declared in scope

I am having an issue trying to convert a number into a string. The purpose is for error checking to make sure the number is of a specific length. I have tried using both to_string() and convert.str() functions but get the same error back when trying to compile.

I am using MinGw g++ to compile and realize I need to tell it I want the C++11 standard, which I believe I have done. My compiler code is as follows:

NPP_SAVE
CD $(CURRENT_DIRECTORY)
C:\MinGW\bin\g++ -std=c++11 "$(FULL_CURRENT_PATH)" -o "$(NAME_PART).exe"
cmd /c $(NAME_PART).exe

Now assuming that is correct, my code for using to_string() is as follows:

#include <iostream>
#include <sstream>
#include <string>
using namespace std;

int main() {
  int book_code = 0;

  cout << "Please enter the four digit book code: ";
  cin >> book_code;
  string code = to_string(book_code);

  while (!(cin >> book_code) || code.length() != 4){
    cin.clear();
    cin.ignore(10000, '\n');
    cout << "That is not a valid code." << endl;
    cout << "Please enter the four digit book code: ";
  }
} 

And my code for using convert.str() is as follows:

int main() {
  int book_code = 0;

  cout << "Please enter the four digit book code: ";
  cin >> book_code;
  ostringstream Convert;
  convert << book_code;
  string code = convert.str();

  while (!(cin >> book_code) || code.length() != 4){
    cin.clear();
    cin.ignore(10000, '\n');
    cout << "That is not a valid code." << endl;
    cout << "Please enter the four digit book code: ";
  }
} 

Neither of these was successful and both returned

error: 'to_string' was not declared in this scope

Am I missing something obvious?

like image 394
Grr Avatar asked Dec 03 '25 09:12

Grr


1 Answers

In MinGW std::to_string() does not exist, you should declare your own implementation.

std::string to_string(int i)
{
    std::stringstream ss;
    ss << i;
    return ss.str();
}

I recommend you to use MSYS2, it is more actualizated and you can avoid this type of problems.

Edit:

Checking the dot position in double:

#include <iostream>
#include <sstream>
#include <string>

std::string to_str_with_dot_pos(double i, unsigned int &pos)
{
    std::stringstream ss;
    ss << i;

    std::string result(ss.str());

    pos = 0;
    while (pos < result.length() && result[pos] != '.') {
        pos += 1;
    }

    return result;
}

int main(int argc, char **argv)
{
    double d(12.54);
    unsigned int pos(0);

    // str should be "12.54".
    // pos should be 2.
    std::string str = to_str_with_dot_pos(d, pos);
    std::cout << "double as string: " << str << std::endl;
    std::cout << "double dot position: " << pos << std::endl;

    return 0;
}

Explanation of the code (the while loop):

It gets every character of the std::string and checks if it does not equals to the . dot character, if the character is not equal to . it will add +1 to the pos variable.

It returns 2 and not 3 because we're counting from 0, not 1.

Also, this question is a duplicate.

like image 78
Jean Pierre Dudey Avatar answered Dec 05 '25 23:12

Jean Pierre Dudey



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