Testing if value is in list/array (Ti-Basic)

Question

Is there a way to test if a value is in a list? In Python, I think you can do something like 'if n in myList: print("Value N is in the list.")'

I don't want to use a for loop to check each value seperately, unless it's the only option. I'm using a Ti-84 Plus.

Answer 1

This should work assuming I've thought through it correctly. It's very simple, where L₁ is the list to search and X is the value to look for.

max(not(L₁-X

Step-by-step analysis:

1. L₁-X: Subtract the value from everything in the list. Now, if this list contains a zero, it means our value was in L₁.
2. not(L₁-X: Invert everything in the list. This converts all zeroes to ones, and everything else to zeroes. Now, if this list contains a one, it means our value was in L₁. If the list is all zeroes, it was not.
3. max(not(L₁-X: Get the maximum value in the list. As stated above, the list will be all zeroes if the value was not inside L₁, so the maximum value will be zero. If L₁ had the value inside, the maximum will be a one.

This makes a check as simple as this:

If max(not(L₁-X
Disp "The value was found:",X