var dict = ["alpha": ["a", "b", "c", "d"]]
// output : ["alpha": ["a", "b", "c", "d"]]
var alphaList = dict["alpha"]
// output : {["a", "b", "c", "d"]
alphaList?.removeAtIndex(1)
// output : {Some "b"}
alphaList
// output : {["a", "c", "d"]}
dict
// output : ["alpha": ["a", "b", "c", "d"]]
Why is 'dict' not altered? Is it because 'alphaList' is a copy of the array and not the actual array inside the dictionary? Can anyone point me where in Swift language documentation I can find this information?
What is the correct/functional way to manipulate values (of complex type) of a dictionary?
Good question yes it creates the copy of the value in your case the value is Array
var alphaList = dict["alpha"]
/* which is the copy of original array
changing it will change the local array alphaList as you can see by your output */
output : {Some "b"}
In order to get the original array directly use
dict["alpha"]?.removeAtIndex(1)
Or update it using the key
alphaList?.removeAtIndex(1)
dict["alpha"] = alphaList
Apple : Assignment and Copy Behavior for Strings, Arrays, and Dictionaries
Swift’s String, Array, and Dictionary types are implemented as structures. This means that strings, arrays, and dictionaries are copied when they are assigned to a new constant or variable, or when they are passed to a function or method.
This behavior is different from NSString, NSArray, and NSDictionary in Foundation, which are implemented as classes, not structures. NSString, NSArray, and NSDictionary instances are always assigned and passed around as a reference to an existing instance, rather than as a copy. "
Swift arrays and dictionaries are value (struct) times. There are only one reference to such instance. While NSArray and NSDictonary are class type and there could be multiple references to such instances.
The statement var alphaList = dict["alpha"] makes copy for ["a", "b", "c", "d"], so you cannot change the original array.
If you want to mutate original "alpha" you have to use dict as root variable:
dict["alpha"]?.removeAtIndex(1)
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