Sum out of grep -c

Question

I am trying to find the number an even occured in my log file.

Command:

grep -Eo "2016-08-30" applciationLog.log* -c 

Output:

 applciationLog.log.1:0
 applciationLog.log.2:0
 applciationLog.log.3:0
 applciationLog.log.4:0
 applciationLog.log.5:7684
 applciationLog.log.6:9142
 applciationLog.log.7:8699
 applciationLog.log.8:0

What I actually need is sum of all these values 7684 + 9142 + 8699 = 25525. Any suggestion I can do it? Anything I can append to the grep to enable it.

Any help or pointers are welcome and appreciated.

Answer 1

As addition to the already given answer by ghoti:

You can avoid awk -F: by using grep -h:

grep -c -h -F "2016-08-30" applicationLog.log* | awk '{n+=$0} END {print n}'

This means no filenames and only the counts are printed by grep and we can use the first field for the addition in awk.