I have a Dataframe like this (in Pyspark 2.3.1):
from pyspark.sql import Row
my_data = spark.createDataFrame([
Row(a=[9, 3, 4], b=['a', 'b', 'c'], mask=[True, False, False]),
Row(a=[7, 2, 6, 4], b=['w', 'x', 'y', 'z'], mask=[True, False, True, False])
])
my_data.show(truncate=False)
#+------------+------------+--------------------------+
#|a |b |mask |
#+------------+------------+--------------------------+
#|[9, 3, 4] |[a, b, c] |[true, false, false] |
#|[7, 2, 6, 4]|[w, x, y, z]|[true, false, true, false]|
#+------------+------------+--------------------------+
Now I'd like to use the mask column in order to subset the a and b columns:
my_desired_output = spark.createDataFrame([
Row(a=[9], b=['a']),
Row(a=[7, 6], b=['w', 'y'])
])
my_desired_output.show(truncate=False)
#+------+------+
#|a |b |
#+------+------+
#|[9] |[a] |
#|[7, 6]|[w, y]|
#+------+------+
What's the "idiomatic" way to achieve this? The current solution I have involves map-ing over the underlying RDD and subsetting with Numpy, which seems inelegant:
import numpy as np
def subset_with_mask(row):
mask = np.asarray(row.mask)
a_masked = np.asarray(row.a)[mask].tolist()
b_masked = np.asarray(row.b)[mask].tolist()
return Row(a=a_masked, b=b_masked)
my_desired_output = spark.createDataFrame(my_data.rdd.map(subset_with_mask))
Is this the best way to go, or is there something better (less verbose and/or more efficient) I can do using Spark SQL tools?
One option is to use a UDF, which you can optionally specialize by the data type in the array:
import numpy as np
import pyspark.sql.functions as F
import pyspark.sql.types as T
def _mask_list(lst, mask):
return np.asarray(lst)[mask].tolist()
mask_array_int = F.udf(_mask_list, T.ArrayType(T.IntegerType()))
mask_array_str = F.udf(_mask_list, T.ArrayType(T.StringType()))
my_desired_output = my_data
my_desired_output = my_desired_output.withColumn(
'a', mask_array_int(F.col('a'), F.col('mask'))
)
my_desired_output = my_desired_output.withColumn(
'b', mask_array_str(F.col('b'), F.col('mask'))
)
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