Stream to array convertor without slurp

Question

My JSON input:

  {  "Key": "Team",     "Value": "AA" }
  {  "Key": "Division", "Value": "BB" }

Desired output:

[
  {  "Key": "Team",     "Value": "AA" },
  {  "Key": "Division", "Value": "BB" }
]

I cannot use the --slurp option because I'm in a middle of complex jq code.

The mentioned input is a result of my function and I need to convert it to an array for further processing.

The solution recommended in FAQ: https://github.com/stedolan/jq/wiki/FAQ#general-questions

cat json | jq 'reduce . as $i ([]; . + [$i])'

produces something different:

[
  {  "Key": "Team",     "Value": "AA" }
]
[
  {  "Key": "Division", "Value": "BB" }
]

Answer 1

If your input really is irredeemably a stream, and if you cannot use the slurp option, then the simplest would probably be to use jq 1.5's inputs filter, along the lines of: jq -n '[inputs]'

If you don't use the -n option, then the first JSON entity won't be seen by inputs. If you cannot use the -n option, then use [., inputs]

Answer 2

I think all you need is to use the jq array constructor syntax. I.e. enclose whatever complex expression you have that generates the stream in a pair of [ ]

Here is an example. For the sake of argument I'll use a function in place of whatever complex expression you have. e.g.

def some_complex_expression:
  {  "Key": "Team",     "Value": "AA" },
  {  "Key": "Division", "Value": "BB" }
;

If we just execute this expression

some_complex_expression

the result is a stream of two objects as we expect:

{
  "Key": "Team",
  "Value": "AA"
}
{
  "Key": "Division",
  "Value": "BB"
}

But if we enclose the expression in [ ]

[ some_complex_expression ]

the result is a single array containing the objects from the stream

[
  {
    "Key": "Team",
    "Value": "AA"
  },
  {
    "Key": "Division",
    "Value": "BB"
  }
]