Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Stream / IntRange over 2D coordinates?

I have the following classes:

public class Rectangle
{
   public int width, height;
   public Point start;

   public Rectangle(Point start, int width, int height)
   {
      this.start = start;
      this.width = width;
      this.height = height;
   }
}

public class Point
{
   public int x, y;

   public Point(int x, int y)
   {
      this.x = x;
      this.y = y;
   }
}

I want to make a method of the Rectangle class such that a Java 8 Stream of type Point is returned where it would stream index locations inside the rectangle. Ex.

// This is inside the rectangle class.
public Stream<Point> stream(int hstep, int vstep)
{
   // if the rectangle started at 0,0
   // and had a width and height of 100
   // and hstep and vstep were both 1
   // then the returned stream would be
   // 0,0 -> 1,0 -> 2,0 -> ... -> 100,0 -> 0,1 -> 1,1 -> ...

   // If vstep was 5 and h step was 25 it would return
   // 0,0 -> 25,0 -> 50,0 -> 75,0 -> 100,0 -> 0,5 -> 25,5 -> ...

   return ...
}

I've used IntStream a lot, map, filter, etc but this is much more complicated then anything I've ever tried. I have no idea how I would do something like that. Can someone steer me int he right direction?

like image 205
Hatefiend Avatar asked Jan 27 '26 02:01

Hatefiend


1 Answers

You can use a nested IntStream to generate each Point, then flatten the resulting stream:

public Stream<Point> stream(int hstep, int vstep) {
    return IntStream.range(0, height / vstep)
            .mapToObj(y -> IntStream.range(0, width / hstep)
                    .mapToObj(x -> new Point(start.x + x * hstep, start.y + y * vstep)))
            .flatMap(Function.identity());
}
like image 131
shmosel Avatar answered Jan 29 '26 15:01

shmosel



Donate For Us

If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!