split username & password from URL in 3.8+ (splituser is deprecated, no alternative)

Question

trying to filter out the user-password from a URL.

(I could've split it manually by the last '@' sign, but I'd rather use a parser)

Python gives a deprecation warning but urlparse() doesn't handle user/password.

Should I just trust the last-@-sign, or is there a new version of split-user?

Python 3.8.2 (default, Jul 16 2020, 14:00:26) 
[GCC 9.3.0] on linux
>>> url="http://usr:[email protected]/path&var=val"
>>> import urllib.parse

>>> urllib.parse.splituser(url)
<stdin>:1: DeprecationWarning: urllib.parse.splituser() is deprecated as of 3.8, use urllib.parse.urlparse() instead
('http://usr:pswd', 'www.site.com/path&var=val')

>>> urllib.parse.urlparse(url)
ParseResult(scheme='http', netloc='usr:[email protected]', path='/path&var=val', params='', query='', fragment='') 

#neigher with allow_fragments:

>>> urllib.parse.urlparse(url,allow_fragments=True)
ParseResult(scheme='http', netloc='us:[email protected]', path='/all', params='', query='var=val', fragment='')

(Edit: the repr() output is partial & misleading; see my answer.)

Answer 1

It's all there, clear and accessible.

What went wrong: The repr() here is misleading, showing only few properties / values (why? it's another question).

The result is available with explicit property get:

>>> url = 'http://usr:[email protected]:8082/nativ/page?vari=valu'
>>> p = urllib.parse.urlparse(url)

>>> p.port
8082
>>> p.hostname
'www.sharat.uk'
>>> p.password
'pswd'
>>> p.username
'usr'
>>> p.path
'/nativ/page'
>>> p.query
'vari=valu'
>>> p.scheme
'http'

Or as a one-liner (I just needed the domain):

>>> urllib.parse.urlparse('http://usr:[email protected]:8082/nativ/page?vari=valu').hostname
www.shahart.uk