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I am trying to extract php code from a long file. I wish to throw away the code not in a PHP tags. Example
<html>hello world, its a wonderful day</html>
<?php echo $user_name; ?> Some more text or HTML <?php echo $datetime; ?>
I just echoed the user_name and datetime variables.
I want to return an array with:
array(
[1] => "<?php echo $user_name; ?>"
[2] => "<?php echo $datetime; ?>"
)
I think I can do this with regex but im not an expert. Any help? Im writing this in PHP. :)
715
You will have to view the source code in order to see the results, but this is what I came up with:
$string = '<html>hello world, its a wonderful day</html>
<?php echo $user_name; ?> Some more text or HTML <?php echo $datetime; ?>
I just echoed the user_name and datetime variables.';
preg_match_all("/<\?php(.*?)\?>/",$string,$matches);
print_r($matches[0]); // for php tags
print_r($matches[1]); // for no php tags
Update: As mentioned by Revent, you could have <?= for shorthand echo statments. It would be possible to change your preg_match_all to include this:
$string = '<html>hello world, its a wonderful day</html>
<?php echo $user_name; ?> Some more text or HTML <?= $datetime; ?>
I just echoed the user_name and datetime variables.';
preg_match_all("/<\?(php|=)(.*?)\?>/",$string,$matches);
print_r($matches[0]); // for php tags
print_r($matches[1]); // for no php tags
Another alternative is to check for <?(space) for the shorthand php statement. You can include a space (\s) to check for this:
preg_match_all("/<\?+(php|=|\s)(.*?)\?>/",$string,$matches);
I guess it just depends on how "strict", you want to be.
Update2: MikeM does make a good point, about being aware of line breaks. You may run into an instance where your tags run over into the next line:
<?php
echo $user_name;
?>
This can easily be solved by using the s modifier to skip linbreaks:
preg_match_all("/<\?+(php|=|\s)(.*?)\?>/s",$string,$matches);
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