Sort dict by key and retrieve value

Question

Given scores = { 0.0: "bob", 5.2: "alex", 2.8: "carl"}

To get the output [ "bob", "carl", "alex" ]

I can do print([ scores[key] for key in sorted(scores.keys()) ])

Is this the best (most "pythonic") way? I was thinking I could use scores.items() in conjunction with sorted(key=...) to avoid the dictionary lookup, but not sure what that key parameter would be.

Answer 1

Iterating over dict will always use the keys, so you don't have to use the .keys() method.

Also, try not to use space after and before parenthesis.

scores = {0.0: "bob", 5.2: "alex", 2.8: "carl"}
print([scores[key] for key in sorted(scores)])

For more functional approach, you can also use:

scores = {0.0: "bob", 5.2: "alex", 2.8: "carl"}
print(list(map(scores.get, sorted(scores))))

But your solution is perfectly fine :)

Answer 2

Another approach would be to create a generator object yielding the values of the dict, cast them to a list and then print it.

print(list(val for val in scores.values()))