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Resizing image and its bounding box

I have an image with bounding box in it, and I want to resize the image.

img = cv2.imread("img.jpg",3)
x_ = img.shape[0]
y_ = img.shape[1]
img = cv2.resize(img,(416,416));

Now I want to calculate the scale factor:

x_scale = ( 416 / x_)
y_scale = ( 416 / y_ )

And draw an image, this is the code for the original bounding box:

( 128, 25, 447, 375 ) = ( xmin,ymin,xmax,ymax)
x = int(np.round(128*x_scale))
y = int(np.round(25*y_scale))
xmax= int(np.round  (447*(x_scale)))
ymax= int(np.round(375*y_scale))

However using this I get:

enter image description here

While the original is:

enter image description here

I don't see any flag in this logic, what's wrong?

Whole code:

imageToPredict = cv2.imread("img.jpg",3)
print(imageToPredict.shape)

x_ = imageToPredict.shape[0]
y_ = imageToPredict.shape[1]

x_scale = 416/x_
y_scale = 416/y_
print(x_scale,y_scale)
img = cv2.resize(imageToPredict,(416,416));
img = np.array(img);


x = int(np.round(128*x_scale))
y = int(np.round(25*y_scale))
xmax= int(np.round  (447*(x_scale)))
ymax= int(np.round(375*y_scale))
Box.drawBox([[1,0, x,y,xmax,ymax]],img)

and drawbox

def drawBox(boxes, image):
    for i in range (0, len(boxes)):
        cv2.rectangle(image,(boxes[i][2],boxes[i][3]),(boxes[i][4],boxes[i][5]),(0,0,120),3)
    cv2.imshow("img",image)
    cv2.waitKey(0)
    cv2.destroyAllWindows()

The image and the data for the bounding box are loaded separately. I am drawing the bounding box inside the image. The image does not contain the box itself.

like image 234
jejjejd Avatar asked Sep 01 '25 03:09

jejjejd


1 Answers

I believe there are two issues:

  1. You should swap x_ and y_ because shape[0] is actually y-dimension and shape[1] is the x-dimension
  2. You should use the same coordinates on the original and scaled image. On your original image the rectangle is (160, 35) - (555, 470) rather than (128,25) - (447,375) that you use in the code.

If I use the following code:

import cv2
import numpy as np


def drawBox(boxes, image):
    for i in range(0, len(boxes)):
        # changed color and width to make it visible
        cv2.rectangle(image, (boxes[i][2], boxes[i][3]), (boxes[i][4], boxes[i][5]), (255, 0, 0), 1)
    cv2.imshow("img", image)
    cv2.waitKey(0)
    cv2.destroyAllWindows()


def cvTest():
    # imageToPredict = cv2.imread("img.jpg", 3)
    imageToPredict = cv2.imread("49466033\\img.png ", 3)
    print(imageToPredict.shape)

    # Note: flipped comparing to your original code!
    # x_ = imageToPredict.shape[0]
    # y_ = imageToPredict.shape[1]
    y_ = imageToPredict.shape[0]
    x_ = imageToPredict.shape[1]

    targetSize = 416
    x_scale = targetSize / x_
    y_scale = targetSize / y_
    print(x_scale, y_scale)
    img = cv2.resize(imageToPredict, (targetSize, targetSize));
    print(img.shape)
    img = np.array(img);

    # original frame as named values
    (origLeft, origTop, origRight, origBottom) = (160, 35, 555, 470)

    x = int(np.round(origLeft * x_scale))
    y = int(np.round(origTop * y_scale))
    xmax = int(np.round(origRight * x_scale))
    ymax = int(np.round(origBottom * y_scale))
    # Box.drawBox([[1, 0, x, y, xmax, ymax]], img)
    drawBox([[1, 0, x, y, xmax, ymax]], img)


cvTest()

and use your "original" image as "49466033\img.png",

Original image

I get the following image

Processed image

And as you can see my thinner blue line lies exactly inside your original red line and it stays there whatever targetSize you chose (so the scaling actually works correctly).

like image 96
SergGr Avatar answered Sep 02 '25 17:09

SergGr