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Replace all characters except for the last occurrence

Tags:

go

I am performing a replace of characters on a string like this:

result = strings.ReplaceAll(result, ".", "_")

This works as expected, but I want to preserve the last occurence of the . and not replace it, just leave it alone.

Is there a fancy way doing this?

like image 676
Blankman Avatar asked Oct 15 '25 15:10

Blankman


2 Answers

The most obvious way to handle this would be to combine Replace and Count:

func ReplaceAllExceptLast(d string, o string, n string) string {
    strings.Replace(d, o, n, strings.Count(d, o) - 1)
}

I don't think this would be the most optimal solution, however. For me, the best option would be to do this:

func ReplaceAllExceptLast(d string, o string, n string) string {
    ln := strings.LastIndex(d, o)
    if ln == -1 {
        return d
    }

    return strings.ReplaceAll(d[:ln], o, n) + d[ln:]
}

This works by getting the index of the last occurrence of the value you want to replace, and then doing a replace-all on the string up to that point. For example:

println(ReplaceAllExceptLast("a", ".", "_"))
println(ReplaceAllExceptLast("a.b", ".", "_"))
println(ReplaceAllExceptLast("a.b.c", ".", "_"))
println(ReplaceAllExceptLast("a.b.c.d", ".", "_"))

will produce:

a
a.b
a_b.c
a_b_c.d
like image 56
Woody1193 Avatar answered Oct 17 '25 09:10

Woody1193


Split into []string, then Join all but last ;)

func ReplaceAllButLast(data, old, new string) string {
    split := strings.Split(data, old)
    if len(split) < 3 {
        return data
    }
    last := len(split) - 1
    return strings.Join(split[:last], new) + old + split[last]
}

https://go.dev/play/p/j8JJP-p_Abk

func main() {
    println(ReplaceAllButLast("a", ".", "_"))
    println(ReplaceAllButLast("a.b", ".", "_"))
    println(ReplaceAllButLast("a.b.c", ".", "_"))
    println(ReplaceAllButLast("a.b.c.d", ".", "_"))
}

produced

a
a.b
a_b.c
a_b_c.d

UPDATE

That was a joke, just to be fancy

Best way is to count the number of matches and replace Count()-1, the second it to ReplaceAll until last match position and using Join to be the slowest

func ReplaceAllButLast_Count(data, old, new string) string {
    cnt := strings.Count(data, old)
    if cnt < 2 {
        return data
    }
    return strings.Replace(data, old, new, cnt-1)
}

func ReplaceAllButLast_Replace(data, old, new string) string {
    idx := strings.LastIndex(data, old)
    if idx <= 0 {
        return data
    }

    return strings.ReplaceAll(data[:idx], old, new) + data[idx:]
}

func ReplaceAllButLast_Join(data, old, new string) string {
    split := strings.Split(data, old)
    if len(split) < 3 {
        return data
    }
    last := len(split) - 1
    return strings.Join(split[:last], new) + old + split[last]
}

Benchmark using a.b.c.d -> a_b_c.d

goos: windows
goarch: amd64
pkg: example.org
cpu: Intel(R) Core(TM) i7-8550U CPU @ 1.80GHz
Benchmark_Count-8       16375098            70.05 ns/op        8 B/op          1 allocs/op
Benchmark_Replace-8     11213830           108.5 ns/op        16 B/op          2 allocs/op
Benchmark_Slice-8        5460445           217.6 ns/op        80 B/op          3 allocs/op
like image 35
Pak Uula Avatar answered Oct 17 '25 11:10

Pak Uula



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