I have a vector in Matlab B of dimension nx1 that contains the integers from 1 to n in a certain order, e.g. n=6 B=(2;4;5;1;6;3).
I have a vector A of dimension mx1 with m>1 that contains the same integers in ascending order each one repeated an arbitrary number of times, e.g. m=13 A=(1;1;1;2;3;3;3;4;5;5;5;5;6).
I want to get C of dimension mx1 in which the integers in A are reordered following the order in B. In the example, C=(2;4;5;5;5;5;1;1;1;6;3;3;3)
One approach with ismember and sort -
[~,idx] = ismember(A,B)
[~,sorted_idx] = sort(idx)
C = B(idx(sorted_idx))
If you are into one-liners, then another with bsxfun -
C = B(nonzeros(bsxfun(@times,bsxfun(@eq,A,B.'),1:numel(B))))
This requires just one sort and indexing:
ind = 1:numel(B);
ind(B) = ind;
C = B(sort(ind(A)));
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