I have a numpy array:
a = np.array([-1,2,3,-1,5,-2,2,9])
I want to only keep values in the array which occurs more than 2 times, so the result should be:
a = np.array([-1,2,-1,2])
Is there a way to do this only using numpy? I have a solution using a dictionary and dictionary filtering, but this is kind of slow, and I was wondering if there was a faster solution only using numpy.
Thanks !
import numpy as np
a = np.array([-1, 2, 3, -1, 5, -2, 2, 9])
values, counts = np.unique(a, return_counts=True)
values_filtered = values[counts >= 2]
result = a[np.isin(a, values_filtered)]
print(result) # return [-1 2 -1 2]
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