Remove an array item from Nested array using Lodash

Question

Looking to remove an array item from the nested array if subset array have value a null or 0(zero) using lodash. I tried filter but I am looking for best way in term of performance.

const arr = [["a","b","c"],["f","r","p",0],["r",22,null,"t"],["d","e","f"]];
console.log("arr", arr);
// output should be [["a","b","c"],["d","e","f"]]

Answer 1

You can use filter() and some()

const arr = [["a","b","c"],["f","r","p",0],["r",22,null,"t"],["d","e","f"]];

let res = arr.filter(x => !x.some(a => a === null || a === 0))
console.log(res)

Answer 2

• With lodash : filter and includes functions:

const arr = [["a","b","c"],["f","r","p",0],["r",22,null,"t"],["d","e","f"]];
const result = _.filter(arr, x => !_.includes(x, null) && !_.includes(x, 0))
console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.14/lodash.min.js"></script>

• With ES6 : filter and some functions:

const arr = [["a","b","c"],["f","r","p",0],["r",22,null,"t"],["d","e","f"]];
const result = arr.filter( x => !x.some(s => s === null || s === 0))
console.log(result)

• With ES6 : reduce:

const arr = [["a","b","c"],["f","r","p",0],["r",22,null,"t"],["d","e","f"]];
const result = arr.reduce( (acc, c) => {
  if(c.some(x => x === null || x === 0)) {
    return acc
  }
  return [...acc, c]
},[])

console.log(result)