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testing= testing.match(/(\d{5})/g); I'm reading a full html into variable. From the variable, want to grab out all numbers with the pattern of exactly 5 digits. No need to care of whether before/after this digit having other type of words. Just want to make sure whatever that is 5 digit numbers been grabbed out.
However, when I apply it, it not only pull out number with exactly 5 digit, number with more than 5 digits also retrieved...
I had tried putting ^ in front and $ behind, but it making result come out as null.
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match(/(\d{5})/g);
To match any number from 0 to 9 we use \d in regex. It will match any single digit number from 0 to 9. \d means [0-9] or match any number from 0 to 9. Instead of writing 0123456789 the shorthand version is [0-9] where [] is used for character range.
Occurrence Indicators (or Repetition Operators): +: one or more ( 1+ ), e.g., [0-9]+ matches one or more digits such as '123' , '000' . *: zero or more ( 0+ ), e.g., [0-9]* matches zero or more digits. It accepts all those in [0-9]+ plus the empty string.
How Many 5-Digit Numbers are there? There are 90,000 five-digit numbers including the smallest five-digit number which is 10,000 and the largest five-digit number which is 99,999.
I am reading a text file and want to use regex below to pull out numbers with exactly 5 digit, ignoring alphabets.
Try this...
var str = 'f 34 545 323 12345 54321 123456', matches = str.match(/\b\d{5}\b/g); console.log(matches); // ["12345", "54321"] jsFiddle.
The word boundary \b is your friend here.
My regex will get a number like this 12345, but not like a12345. The other answers provide great regexes if you require the latter.
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