Python finding n consecutive numbers in a list

Question

I want to know how to find if there is a certain amount of consecutive numbers in a row in my list e.g.

For example if I am looking for two 1's then:

list = [1, 1, 1, 4, 6] #original list
list = ["true", "true", 1, 4, 6] #after my function has been through the list.

If I am looking for three 1's then:

list = [1, 1, 1, 4, 6] #original list
list = ["true", "true", "true", 4, 6] #after my function has been through the list.

I have tried:

list = [1, 1, 2, 1]

1,1,1 in list #typed into shell, returns "(1, 1, True)"

Any help would be greatly appreciated, I mainly would like to understand whats going on, and how to check if the next element in the list is the same as the first x amount.

Answer 1

It is a bad idea to assign to list. Use a different name.

To find the largest number of consecutive equal values you can use itertools.groupby

>>> import itertools
>>> l = [1, 1, 1, 4, 6]
>>> max(len(list(v)) for g,v in itertools.groupby(l)) 
3

To search only for consecutive 1s:

>>> max(len(list(v)) for g,v in itertools.groupby(l, lambda x: x == 1) if g) 
3