I couldn't find any workaround for this. In my real example this will serve to associate color masks with objects.
I think the best way to explain is give an example:
objects = ['pencil','pen','keyboard','table','phone']
colors = ['red','green','blue']
for n, i in enumerate(objects):
print n,i #0 pencil
# print the index of colors
The result I need:
#0 pencil # 0 red
#1 pen # 1 green
#2 keyboard # 2 blue
#3 table # 0 red
#4 phone # 1 green
So, there will be always 3 colors to associate with the objects, How can I get this result within a for loop in python? Every time the n (iterator) is bigger than the length of the colors list, how can I tell it to go back and print the first index and so on?
Use %:
for n, obj in enumerate(objects):
print n, obj, colors[n % len(colors)]
or zip() and itertools.cycle():
from itertools import cycle
for n, (obj, color) in enumerate(zip(objects, cycle(colors))):
print n, obj, color
Demo:
>>> objects = ['pencil','pen','keyboard','table','phone']
>>> colors = ['red','green','blue']
>>> for n, obj in enumerate(objects):
... print n, obj, colors[n % len(colors)]
...
0 pencil red
1 pen green
2 keyboard blue
3 table red
4 phone green
>>> from itertools import cycle
>>> for n, (obj, color) in enumerate(zip(objects, cycle(colors))):
... print n, obj, color
...
0 pencil red
1 pen green
2 keyboard blue
3 table red
4 phone green
>>> from itertools import count, izip, cycle
>>> objects = ['pencil','pen','keyboard','table','phone']
>>> colors = ['red','green','blue']
>>> for i, obj, color in izip(count(), objects, cycle(colors)):
... print i, obj, color
...
0 pencil red
1 pen green
2 keyboard blue
3 table red
4 phone green
or
>>> for i, obj, j, color in izip(count(), objects, cycle(range(len(colors))), cycle(colors)):
... print i, obj, j, color
...
0 pencil 0 red
1 pen 1 green
2 keyboard 2 blue
3 table 0 red
4 phone 1 green
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