Printing out ordinals

Question

Here I'm trying to create a function which accepts n number of integers and sum them together... But I'm having trouble having it print the correct ordinals. Am I using a wrong loop?

int i, count, sum, number;
sum = 0;
count = 0;


printf("Please indicate the number of integers:");
scanf("%d", &count);

for (i=0; i<count; i++){
    printf("Please input the %dst number:", i+1);
    scanf("%d", &number);

    sum = sum + number;
}

printf("sum is %d\n", sum);
return 0;

For example if i input count = 5, it will print

Please input the 1st number:
Please input the 2st number:
Please input the 3st number:
Please input the 4st number:
Please input the 5st number:
sum is 15

It prints the correct sum, but I want it to print the correct ordinal for every line.. for example, 2nd..3rd. Possibly without having to use an array

Answer 1

In English, rules for ordinals are fairly simple (note: not "simple," but "fairly simple"):

1. Below zero, you're on your own. Some might apply positive-number rules, others say it makes no sense to try a negative ordinal.

2. Most ordinals end with 'th':

   • fourth
   • thirty-ninth

3. Numbers ending with 1, 2, 3 are different:

   • first
   • twenty-second
   • one hundred eighty-third

4. Except that numbers ending in 11, 12, 13 are 'th' numbers, because English treats the teens differently (six-teen vs. twenty-six). So:

   • eleventh
   • one hundred twelfth
   • thirteenth

5. In general, only nerds think "zeroth" is funny. But it's still a -th, so it gets the default treatment.

In code:

if (n < 0) { /* Rule 1: good luck */ }

suffix = "th"; /* Rule 2: default = th */

if (1 <= n%10 && n%10 <= 3) { /* Rule 3: 1st, 2nd, 3rd */

    if (n%100 < 10 || n%100 > 20) { /* Rule 4: 11th-13th */
        suffix = (n%10 == 1) ? "st" 
               : (n%10 == 2) ? "nd" 
               :               "rd"
               ;
    }
}