I have an array of vectors (of ints) and I want to pass it to a member function as reference so it can be modified. (It actually is the output of my function but I already have a return value.)
I wrote something like this
int Dag::dag2array(vector<int> (&aVectors)[4])
{
//some stuff
//calling another function tree2array(aVectors)
//passing the same array as reference
}
It compile and runs although it looks like it is not doing what I want.
In a more or less opposite question (Passing array of vectors as a function parameter (values will not change)), the answers say that the array can be modified without & and that it does not make a copy but it is like a pointer.
int one needs the & to avoid
copying and to be able to modify the value of the original variable "on the fly" and not for an array?& or not in my case?This is one of those cases where C arrays just make life difficult. I would strongly recommend using a std::array (or std::tr1::array if you're not using C++11 yet). Rather than that obscure syntax, saying
int func(std::array<std::vector<int>, 4>& vectors)
makes it very clear that you're passing an array of 4 vectors by reference, and thus can modify the values by saying
vectors[1][2] = 19;
or what-have-you.
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