Pass command line parameters to uwsgi script

Question

I'm trying to pass arguments to an example wsgi application, :

config_file = sys.argv[1]  def application(env, start_response):     start_response('200 OK', [('Content-Type','text/html')])     return [b"Hello World %s" % config_file] 

And run:

uwsgi --http :9090 --wsgi-file test_uwsgi.py  -???? config_file # argument for wsgi script 

Any smart way I can achieve it? Couldn't find it in uwsgi docs. Maybe there is another way of providing some parameters to the wsgi application? (env. variables are out of scope)

Answer 1

python args:

--pyargv "foo bar"

sys.argv ['uwsgi', 'foo', 'bar'] 

uwsgi options:

--set foo=bar

uwsgi.opt['foo'] 'bar' 

Answer 2

You could use an .ini file with the pyargv setting that @roberto mentioned. Let's call our config file uwsgi.ini and use the content:

[uwsgi] wsgi-file=/path/to/test_uwsgi.py pyargv=human 

Then let's create a WGSI app to test it:

import sys def application(env, start_response):     start_response('200 OK', [('Content-Type','text/html')])     return [str.encode("Hello " + str(sys.argv[1]), 'utf-8')] 

You can see how to load this file https://uwsgi-docs.readthedocs.io/en/latest/Configuration.html#loading-configuration-files:

 uwsgi --ini /path/to/uwsgi.ini --http :8080 

Then when we curl the app, we can see our param echoed back:

$ curl http://localhost:8080 Hello human 

If you are trying to pass argparse style arguments to your WSGI app, they work just fine in the .ini too:

pyargv=-y /config.yml