Hi I am using paramiko 1.7.6 "fanny" on microsoft windows xp v2002 service pack3 with python 2.4.2
I have the follwing script:
import paramiko
hostname='blah'
port=22
username='blah'
password='blah'
fullpath='\\\\root\\path\\file.xls'
remotepath='/inbox/file.xls'
self.client= paramiko.SSHClient()
self.client.load_system_host_keys()
self.client.connect(hostname,port,username,password)
sftp = self.client.open_sftp()
sftp.put(fullpath,remotepath)
the error I get is:
sftp.put(fullpath,remotepath))
File "build\bdist.win32\egg\paramiko\sftp_client.py", line 577, in put
File "build\bdist.win32\egg\paramiko\sftp_client.py", line 337, in stat
File "build\bdist.win32\egg\paramiko\sftp_client.py", line 628, in _request
File "build\bdist.win32\egg\paramiko\sftp_client.py", line 675, in _read_response
File "build\bdist.win32\egg\paramiko\sftp_client.py", line 701, in _convert_status
IOError: [Errno 2] /inbox/file.xls is not a valid file path
but the path definitely exists (I can move into it using sftp.chdir('inbox')) I have also tried moving into the folder and using put but I get the exact same error (did take out inbox prefix)
Has anyone had this issue?
Cheers matt
IOError: [Errno 2] /inbox/file.xls is not a valid file path
This is your error, which means that /inbox isn't a valid path. You probably meant to use
remotepath='inbox/file.xls'
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