Order the array result using $percent variable php

Question

This is my array:

$mygetting_id = $wpdb->get_results("SELECT DISTINCT post_id,meta_value from wp_postmeta Where meta_value  LIKE '".$search_res[$k]."%' OR meta_value  LIKE '%".$search_res[$k]."%'  AND meta_key='my_profile_tags' ORDER BY post_id $limit");

    foreach ( $mygetting_id as $post )
    {
        $id = $post->post_id;

        $metaValue= esc_attr(get_post_meta($id, 'my_profile_tags',true));
        $array_metaValue = explode(',',$metaValue);
        $array_metaValue = array_map('strtolower', $array_metaValue);
        $total_tags=count($array_metaValue);//like total=10

        for($e=0;$e<=count($search_res);$e++)
        {
            $key = count( array_intersect( $array_metaValue, array_map('strtolower', $search_res ) ) );
        }

        // Get Percentage of each array result.
        $percent=($key/$search_count)*100;
        $percent=round($percent,0);
        ?>

        //html part
    } // for each close

Now I want to ORDER BY or show my result according to $percent variable then after show the results. I can't use the $percent var in my SQL statement. What should I do.

This is how it is displaying right now. I want the 400% to the top.

Answer 1

You can Order the results using PHP usort()

     <?php

     $mygetting_id = $wpdb->get_results("SELECT DISTINCT post_id,meta_value from wp_postmeta Where meta_value  LIKE '".$search_res[$k]."%' OR meta_value  LIKE '%".$search_res[$k]."%'  AND meta_key='my_profile_tags' ORDER BY post_id $limit");

     $sortedResults = array(); 

     foreach ( $mygetting_id as $post )
     {
      $id = $post->post_id;

     $metaValue= esc_attr(get_post_meta($id, 'my_profile_tags',true));
     $array_metaValue = explode(',',$metaValue);
     $array_metaValue = array_map('strtolower', $array_metaValue);
     $total_tags=count($array_metaValue);//like total=10

     for($e=0;$e<=count($search_res);$e++)
     {
         $key = count( array_intersect( $array_metaValue, array_map('strtolower', $search_res ) ) );
     }

     // Get Percentage of each array result.
     $percent=($key/$search_count)*100;
     $percent=round($percent,0);

     // adding percent property to use it in usort
     $post->percent = $percent;

     $sortedResults[] = $post;
     }

    // sorting results
    usort($sortedResults, function($a, $b){
       // in case if they are equal
      if($a == $b) return 0;
      return $a->percent < $b->percent ? 1 : -1;
    });
    /// now your results are sorted do html part
    foreach($sortedResults as $post){
      // do your html here e.g
      echo $post->id;
      echo $post->percent . '%'; // etc
    }

    ?>

or you can store percentage as separate field in the table and just ORDER BY score

Answer 2

You can use complex arithmetic operations in ORDER BY.

So, use the following.

$mygetting_id = $wpdb->get_results("SELECT DISTINCT post_id,meta_value from wp_postmeta Where meta_value  LIKE '".$search_res[$k]."%' OR meta_value  LIKE '%".$search_res[$k]."%'  AND meta_key='my_profile_tags' ORDER BY 


round(($key/$search_count)*100)


 $limit");