Odd behaviors when dividing doubles in Java

Question

When I divide 317 by 219 in Java using doubles I get 1.
For example:

double b = 317/219;
System.out.println(b);

Output is: 1.

Is this because it is a recurring decimal? Have had to use BigDecimal instead which is annoying.

Answer 1

Try this

 double b = 317/219D;

The default type of coded numbers in java is int, so with the code as you have it java is working with two int numbers and the result of the division would then be int too, which will truncate the decimal part to give a final result of 1. This int result is then cast from int 1 to a double 1 without a compiler warning because it's a widening cast (one where the source type is guaranteed to "fit" into the target type).

By coding either of the numbers as double with the trailing D (you may also use d, but I always use upper case letters because L as lowercase l looks like a 1), the result of the division will be double too.

Answer 2

Another alternative...

double b = (double)317/219;