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Number of non-zero pixels in a cv::RotatedRect

as the title says i'm trying to find the number of non-zero pixels in a certain area of a cv::Mat, namely within a RotatedRect.

For a regular Rect one could simply use countNonZeroPixels on a ROI. However ROIs can only be regular (non rotated) rectangles.

Another idea was to draw the rotated rectangle and use that as a mask. However openCV neither supports the drawing of rotated rectangles nor does countNonZeroPixels accept a mask.

Does anyone have a solution for how to elegantly solve this ?

Thank you !

like image 531
joekr Avatar asked Sep 04 '25 01:09

joekr


1 Answers

Ok, so here's my first take at it.

The idea is to rotate the image reverse to the rectangle's rotation and than apply a roi on the straightened rectangle.

  • This will break if the rotated rectangle is not completely within the image
  • You can probably speed this up by applying another roi before rotation to avoid having to rotate the whole image...

    #include <highgui.h>
    #include <cv.h>
    
    
    // From http://stackoverflow.com/questions/2289690/opencv-how-to-rotate-iplimage
    cv::Mat rotateImage(const cv::Mat& source, cv::Point2f center, double angle)
    {
      cv::Mat rot_mat = cv::getRotationMatrix2D(center, angle, 1.0);
      cv::Mat dst;
      cv::warpAffine(source, dst, rot_mat, source.size());
      return dst;
    }
    
    int main()
    {
      cv::namedWindow("test1");
    
      // Our rotated rect
      int x = 300;
      int y = 350;
      int w = 200;
      int h = 50;
      float angle = 47;
      cv::RotatedRect rect = cv::RotatedRect(cv::Point2f(x,y), cv::Size2f(w,h), angle);
    
      // An empty image
      cv::Mat img = cv::Mat(cv::Size(640, 480), CV_8UC3);
    
      // Draw rotated rect as an ellipse to get some visual feedback
      cv::ellipse(img, rect, cv::Scalar(255,0,0), -1);
    
      // Rotate the image by rect.angle * -1
      cv::Mat rotimg = rotateImage(img, rect.center, -1 * rect.angle);
    
      // Set roi to the now unrotated rectangle
      cv::Rect roi;
      roi.x = rect.center.x - (rect.size.width / 2);
      roi.y = rect.center.y - (rect.size.height / 2);
      roi.width = rect.size.width;
      roi.height = rect.size.height;
    
      cv::imshow("test1", rotimg(roi));
      cv::waitKey(0);
    }
    
like image 184
joekr Avatar answered Sep 07 '25 17:09

joekr