i am using MySql workbench 5.7 to run this.
i am trying to get the result of this query:
SELECT COUNT(Users) FROM UserList.custumers;
and this query:
SELECT Users FROM UserList.custumers;
at the same table, meaning i want a list of users in one column and the amount of total users in the other column.
when i tries this:
SELECT Users , COUNT(Users) FROM UserList.custumers;
i get a single row with the right count but only the first user in my list....
You can either use a cross join since you know the count query will result in one row... whose value you want repeated on every row.
SELECt users, userCount
FROM  userlist.custumers
CROSS JOIN  (Select count(*) UserCount from userlist.custumers)
Or you can run a count in the select.... I prefer the first as the count only has to be done once.
SELECT users, (SELECT count(*) cnt FROM userlist.custumers) as userCount 
FROM userlist.custumers
Or in a environment supporting window functions (not mySQL) you could count(*) over (partition by 1) as userCount
The reason you're getting one row is due to mySQL's extension of the GROUP BY which will pick a single value from non-aggregated columns to display when you use aggregation without a group by clause. If you add a group by to your select, you will not get the count of all users. Thus the need for the inline select or the cross join.
Consider: -- 1 record not all users
SELECT Users , COUNT(Users) FROM UserList.custumers;  
vs --all users wrong count
SELECT Users , COUNT(Users) FROM UserList.custumers group by users;
vs -- what I believe you're after
SELECT Users, x.usercount FROM UserList.custumers 
CROSS JOIN  (Select count(*) UserCount from userlist.custumers) x  
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