My second scanf is not working - what can I do?

Question

My second scanf in this code is not working, the computer doesn't wait for me to enter the second value.

I know when it happens with %c it is just need to put a space before the % But can't make it work with %f

#include <stdlib.h>
#include <stdio.h>

main()
{
    float a, p;
    printf("Insira seu peso: "); scanf("%.1f", &p);
    printf("Insira sua altura: "); scanf("%.2f", &a);
}

Answer 1

The dot . is not a valid format flag character in the scanf() family of functions. The formats are related to the printf() family of formats (and that's not accidental) but they are far from identical.

Each conversion specification is introduced by the character '%' … after which the following appear in sequence:

• An optional assignment-suppressing character '*'.

• An optional non-zero decimal integer that specifies the maximum field width.

• [CX] ⌦ An optional assignment-allocation character 'm'. ⌫

• An option length modifier that specifies the size of the receiving object.

• A conversion specifier character that specifies the type of conversion to be applied. The valid conversion specifiers are described below.

No mention of . in there.

Answer 2

Actually not a single scanf is working properly in the code. When we use scanf we are just going to get the answer from the user so we do not need a (.) before the variable "f", float in there. We can make adjustments when we print the number that the user has put. Below I have shown an example:

#include<stdio.h>
#include<stdlib.h>


int main()
{
float a, p;
printf("\n Please enter 1st value: ");
scanf("%f", &p);
printf("\n Please enter 2nd value: ");
scanf("%f", &a);

printf("\n The value of p is: %.1f", p);
printf("\n The value of a is: %.2f", a);



printf("\n\n");

system("PAUSE");
return(0);
}