Javascript improve regex to match number chunks of 3

Question

I want to get a number chunks of 3 if i could by example if i have the number 22345678 i want to get ['22','345','678']. Using the following regex

/(\d{1,3})(?=(\d{3})+(?!\d))/g

I get ['22','345']

Anyone can help me to improve my regex?

An example in here --> https://regex101.com/r/cF6rN4/1 and a snippet in this post

console.log('22345678'.match(/(\d{1,3})(?=(\d{3})+(?!\d))/g));

Answer 1

Match strings which are followed by digits of length as 3's multiplier or at the end.

console.log('22345678'.match(/\d{1,3}(?=(\d{3})+$|$)/g));

Regex explanation here.

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You can avoid the capturing group since it's not necessary.

/\d{1,3}(?=(?:\d{3})+$|$)/g
//---------^^^-------------

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UPDATE : It can be much more simplified by using *(0 or more repetition) instead of +(1 or more repetition) which helps to avoid the pipe symbol. As @torazaburo's comment both (\d{3})*$ and (\d{3})+$|$ are equivalent.

/\d{1,3}(?=(\d{3})*$)/g