Say I have classes Foo
public class Foo {
private Bar bar;
}
and Bar
public class Bar {
private String fizz;
private String bang;
}
EDIT: For clarification I do not own Foo
and Bar
and cannot alter these classes.
If I want to serialize an empty object of type Foo, it's member, which is of type Bar, will be returned as null.
String json = objectMapper.writeValueAsString(new Foo()); // "{"bar" : null}"
Is there any way I can get the object mapper to serialize an empty Bar object without having to instantiate a new instance of Bar and then adding it to a new instance of Foo?
String json = objectMapper.writeValueAsString(new Foo()) // "{bar": {"fizz" : null, "bang" : null } }"
I was also required to produce such a structure for legacy client compatibility, here is my solution (depends on Spring Boot since uses @JsonComponent annotation)
Create "special object" that will be treated as empty
public class EmptyObject {
}
Create property in your model
@JsonProperty("data")
private EmptyObject data = new EmptyObject();
public EmptyObject getData() {
return data;
}
Create serializer that will process empty object above
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.databind.SerializerProvider;
import com.fasterxml.jackson.databind.ser.std.StdSerializer;
import com.sevensenders.datahub.api.service.response.model.EmptyObject;
import org.springframework.boot.jackson.JsonComponent;
import java.io.IOException;
@JsonComponent
public class EmptyObjectSerializer extends StdSerializer<EmptyObject> {
public EmptyObjectSerializer() {
this(null);
}
public EmptyObjectSerializer(Class<EmptyObject> t) {
super(t);
}
@Override
public void serialize(EmptyObject value, JsonGenerator gen, SerializerProvider provider) throws IOException {
// to maintain AF compatible format it is required to write {} instead of null
gen.writeStartObject();
gen.writeEndObject();
}
}
Output:
{
...
"data": {}
}
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