I am using Windows 7 and have both Python 2.7.5 and 3.3.2 installed. My path environment variable is set as
C:\Program Files\Intel\WiFi\bin\;C:\Program Files\Common Files\Intel\WirelessCommon\;C:\python27;C:\Python33\Scripts
When I import any Python module into another module a .pyc file is created. The place where it is created depends on whether Python2 is invoked or Python3 to run it.
.pyc file is created in the same directory #! Python3 at the top then double-clicking makes the .pyc file in the sub-directory.I understand that the reason for this is because of difference in how Python2 and Python3 have decided to manage the byte-compiled codes.
I am currently focusing on Python3 and want the files to be created in subdirectory only.
I tried editing the path variable to place Python3 before Python 2 so that Python3 should be invoked instead of Python2. Even after changing it when I double-click the Python script that didn't happen and the byte-compiled code was created in the same directory.
So Python2 was used to run the Python script on double-clicking. What is causing this behaviour and how can I make sure that Python3 is invoked instead of Python2 without uninstalling Python2?
Python 3 has changed how the bytecode (.pyc) files are stored. Python 2 uses the convention of putting them in the same directory, but for Python 3 the developers decided to reduce clutter by putting them all in a separate directory. This also made support for Python implementations other than CPython easier, as each implementation could have its own .pyc files in the __pycache__ directory rather than overwriting those from other implementations.
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