Here is my code
#include <stdio.h>
char func_with_ret()
{
return 1;
}
void func_1()
{
char buf[16];
func_with_ret();
}
void func_2()
{
char buf[16];
getchar();
}
int main()
{
func_1();
func_2();
}
Here is the disassembly code by gdb for func_1 and func_2.
Dump of assembler code for function func_1:
0x08048427 <+0>: push ebp
0x08048428 <+1>: mov ebp,esp
0x0804842a <+3>: sub esp,0x10
0x0804842d <+6>: call 0x804841d <func_with_ret>
0x08048432 <+11>: leave
0x08048433 <+12>: ret
Dump of assembler code for function func_2:
0x08048434 <+0>: push ebp
0x08048435 <+1>: mov ebp,esp
0x08048437 <+3>: sub esp,0x18
0x0804843a <+6>: call 0x80482f0 <getchar@plt>
0x0804843f <+11>: leave
0x08048440 <+12>: ret
In func_1, buffer is allocated for 0x10(16) bytes, but in func_2 , it is allocated for 0x18(24) bytes, why?
Edit: @Attie figure out that buffer size is actually the same for both, but there's strange 8-byte stack spaces in func_2 don't know where it comes from.
I have just tried to reproduce this, see below:
Compiling for x86-64 (no joy):
$ gcc p.c -g -o p -O0 -fno-stack-protector
$ objdump -d p
p: file format elf64-x86-64
[...]
0000000000400538 <func_1>:
400538: 55 push %rbp
400539: 48 89 e5 mov %rsp,%rbp
40053c: 48 83 ec 10 sub $0x10,%rsp
400540: b8 00 00 00 00 mov $0x0,%eax
400545: e8 e3 ff ff ff callq 40052d <func_with_ret>
40054a: c9 leaveq
40054b: c3 retq
000000000040054c <func_2>:
40054c: 55 push %rbp
40054d: 48 89 e5 mov %rsp,%rbp
400550: 48 83 ec 10 sub $0x10,%rsp
400554: e8 c7 fe ff ff callq 400420 <getchar@plt>
400559: c9 leaveq
40055a: c3 retq
Compiling for i386 (success):
$ gcc p.c -g -o p -O0 -fno-stack-protector -m32
$ objdump -d p
p: file format elf32-i386
[...]
08048427 <func_1>:
8048427: 55 push %ebp
8048428: 89 e5 mov %esp,%ebp
804842a: 83 ec 10 sub $0x10,%esp
804842d: e8 eb ff ff ff call 804841d <func_with_ret>
8048432: c9 leave
8048433: c3 ret
08048434 <func_2>:
8048434: 55 push %ebp
8048435: 89 e5 mov %esp,%ebp
8048437: 83 ec 18 sub $0x18,%esp
804843a: e8 b1 fe ff ff call 80482f0 <getchar@plt>
804843f: c9 leave
8048440: c3 ret
This doesn't appear to be related to any of the following:
getchar() is a library function, and thus we are calling into the PLT (Procedure Linkage Table).main()
If you however increase the size of your buffer by one, to 17, then the stack usage increases to 32 and 40 bytes (from 16 and 24 bytes) respectively. The difference is 16 bytes, which is used for alignment, as answered here.
I can't answer why the stack alignment appears to be off by 8-bytes upon entering func_2() though.
If you update func_1() and func_2() to have a 15-byte buffer, and a single byte variable, and write data to them, then you can see where these items are in the stack frame:
void func_1(void) {
char buf[15];
char x;
buf[0] = 0xaa;
x = 0x55;
func_with_ret();
}
void func_2(void) {
char buf[15];
char x;
buf[0] = 0xaa;
x = 0x55;
getchar();
}
08048434 <func_1>:
8048434: 55 push %ebp
8048435: 89 e5 mov %esp,%ebp
8048437: 83 ec 10 sub $0x10,%esp
804843a: c6 45 f0 aa movb $0xaa,-0x10(%ebp)
804843e: c6 45 ff 55 movb $0x55,-0x1(%ebp)
8048442: e8 d6 ff ff ff call 804841d <func_with_ret>
8048447: c9 leave
8048448: c3 ret
08048449 <func_2>:
8048449: 55 push %ebp
804844a: 89 e5 mov %esp,%ebp
804844c: 83 ec 18 sub $0x18,%esp
804844f: c6 45 e8 aa movb $0xaa,-0x18(%ebp)
8048453: c6 45 f7 55 movb $0x55,-0x9(%ebp)
8048457: e8 94 fe ff ff call 80482f0 <getchar@plt>
804845c: c9 leave
804845d: c3 ret
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