Why does int + BigDecimal not work?

Question

I encountered this problem, which was that I couldn't add an integer to a BigDecimal. In the code, I looked at the error and it said "bad operand types for binary operator '+'". How do I add integer to BigDecimal? (Represented in code as 1 + sqf)

BigDecimal sqf = new BigDecimal(Math.sqrt(5));
sqf.setScale(100);
BigDecimal bd = new BigDecimal((1 + sqf) / 2); //Error here (1 + sqf)
bd.setScale(100);
System.out.println(isBuzzNumber(77707));
System.out.println(findHypotenuse(9, 10));
System.out.println("Phi (φ) = " + bd);

Answer 1

BigDecimal bd = BigDecimal.ONE.add(sqf).divide(new BigDecimal(2))

Standard operators apply to primitives only.

Answer 2

1. Java doesn't have operator overloading, thus any standard operator applies to primitive type only
2. BigDecimal isn't included in the autoboxing mechanism, because it doesn't have primitive type representation
3. Read up BigDecimal API, it implements mathematical operators as methods (which mostly requires another BigDecimal instance as operand.