The code is below. What's the function of dedent()?
When I run this code, the result is virtually the same.
print(dedent("""
Like a world class boxer you dodge, weave, slip and
slide right as the Gothon's blaster cranks a laser
past your head. In the middle of your artful dodge
your foot slips and you bang your head on the metal
wall and pass out. You wake up shortly after only to
die as the Gothon stomps on your head and eats you.
"""))
print("""
Like a world class boxer you dodge, weave, slip and
slide right as the Gothon's blaster cranks a laser
past your head. In the middle of your artful dodge
your foot slips and you bang your head on the metal
wall and pass out. You wake up shortly after only to
die as the Gothon stomps on your head and eats you.
""")
This is based on textwrap.dedent(text).
Consider this example where this can be useful:
import textwrap
# We have some sample data
data = [[13, "John", "New York"],
[25, "Jane", "Madrid"]]
# We create a print function
def printfunc(lst):
# This is the string we want to add data to
how_string_could_look_like = """\
age: {}
name: {}
city: {}
"""
# But we can write it this way instead and use dedent:
# Much easier to read right? (Looks neat inside the function)
string = """\
age: {}
name: {}
city: {}
"""
for item in lst:
p = string.format(*item)
print(p) # Print without dedent
print(textwrap.dedent(p)) # Print with dedent
printfunc(data)
Prints:
Look here at the 1st and 3rd group (no dedent) compared to 2nd and 4th (with dedent). This exemplifies what dedent can do.
age: 13
name: John
city: New York
age: 13
name: John
city: New York
age: 25
name: Jane
city: Madrid
age: 25
name: Jane
city: Madrid
Looking back at your example:
Think about this: What is it I want to textwrap.dedent (remove whitespace before each line)
Full example without comments
data = [[13, "John", "New York"], [25, "Jane", "Madrid"]]
def printfunc(lst):
for item in lst:
string = """\
age: {}
name: {}
city: {}
""".format(*item)
print(textwrap.dedent(string))
printfunc(data)
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