what is the precedence of a ternary operator in this example?

Question

>>> count = 0
>>> for c in "##.#.":
...     count = count + 1 if c == '.' else 0
... 
>>> print(count)
1
>>> count = 0
>>> for c in "##.#.":
...     count = count + (1 if c == '.' else 0)
... 
>>> print(count)
2

Why doesn't the first example print out a counter of 2?

Answer 1

Conditional expressions have a very low precedence.

So the first expression is actually parsed as:

count = (count + 1) if c == '.' else 0

That will set count to 0 every time c != '.'.