What is the meaning of int (*pt)[5] in c [duplicate]

Question

I Have read some where about this type declaration. Declaration is:

int (*arr)[5];

i'm little bit confused with this type declaration.Actually what is the meaning of this declaration and when do we use it.

Answer 1

int *arr[5]

arr is array of 5 pointers

int (*arr)[5]

arr is a pointer to an array of 5 integer elements

Check the code below:

int a[5] = { 1,2,3,4,5};
int (*arr)[5] = &a;
printf("%d",(*arr)[2]);

Now the array element can be accessed like

(*arr)[i] not *arr[i]

Answer 2

According to the “declaration follows use” rule:

• (*arr)[i] is an int, where i < 5, therefore
• *arr is an int[5], an array of five integers, therefore
• arr is an int (*)[5], a pointer to an array of five integers.