The fragments I use in my ViewPager instance are quite resource intensive, so I'd only like to load one at a time. When I try the following:
mViewPager.setOffscreenPageLimit(0);
mViewPager.setAdapter(mPagerAdapter);
My FragmentStatePagerAdapter.getItem(int position) override function is called 3 times, which is what happens when I call mViewPager.setOffscreenPageLimit(1). I would expect it to only be called once, because I specified 0 offscreen pages. 
I believe I'm calling everything correctly, because if I call mViewPager.setOffscreenPageLimit(2), FragmentStatePagerAdapter.getItem(int position) is called 5 times as I would expect. 
Does ViewPager require a minimum of 1 offscreen pages, or am I doing something wrong here?
The best way that I found was setUserVisibleHint
add this to your fragment 
@Override
public void setUserVisibleHint(boolean isVisibleToUser) {
    super.setUserVisibleHint(isVisibleToUser);
    if (isVisibleToUser) {
        // load data here
    }else{
       // fragment is no longer visible
    }
}
Does ViewPager require a minimum of 1 offscreen pages
Yes. If I am reading the source code correctly, you should be getting a warning about this in LogCat, something like:
Requested offscreen page limit 0 too small; defaulting to 1
You can try like this :
public abstract class LazyFragment extends Fragment {
    protected boolean isVisible;
    /**
     * 在这里实现Fragment数据的缓加载.
     * @param isVisibleToUser
     */
    @Override
    public void setUserVisibleHint(boolean isVisibleToUser) {
        super.setUserVisibleHint(isVisibleToUser);
        if(getUserVisibleHint()) {
            isVisible = true;
            onVisible();
        } else {
            isVisible = false;
            onInvisible();
        }
    }
    protected void onVisible(){
        lazyLoad();
    }
    protected abstract void lazyLoad();
    protected void onInvisible(){}protected abstract void lazyLoad();
protected void onInvisible(){}
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