In C++, the following is valid and I can run it without a problem:
int main(){
if (int i=5)
std::cout << i << std::endl;
return 0;
}
However, even though the following should also be valid, it gives me an error:
if ((int i=5) == 5)
std::cout << i << std::endl;
Error:
test.cpp: In function ‘int main()’:
test.cpp:4:10: error: expected primary-expression before ‘int’
if ((int i=5) == 5)
^
test.cpp:4:10: error: expected ‘)’ before ‘int’
test.cpp:5:36: error: expected ‘)’ before ‘;’ token
std::cout << i << std::endl;
^
Furthermore, in C++17 the below code must be valid too, but it gives me a similar error again:
if (int i=5; i == 5)
std::cout << i << std::endl;
Error:
test.cpp: In function ‘int main()’:
test.cpp:4:16: error: expected ‘)’ before ‘;’ token
if (int i=5; i == 5)
^
test.cpp:4:18: error: ‘i’ was not declared in this scope
if (int i=5; i == 5)
^
I am trying to compile with g++ test.cpp -std=c++17. g++ --version gives me g++ (Ubuntu 5.4.0-6ubuntu1~16.04.12) 5.4.0 20160609. What am I missing here?
if ((int i=5) == 5) is a syntax error. It does not match any supported syntax for if statements. The syntax is init-statement(optional) condition, where condition could either be an expression, or a declaration with initializer. You can read more detail about the syntax on cppreference.
if (int i=5; i == 5) is correct. However, you are using an old version of GCC that dates from before C++17 was standardized. You would need to upgrade your compiler version. According to C++ Standards Support in GCC this feature was added in GCC 7.
For starters, I believe your compiler is right to reject
if ((int i=5) == 5)
because this is not legal C++ code. A variable declaration statement isn’t an expression, so you can’t treat (int i = 5) as an expression.
For the second one, I suspect you just need to update your compiler. g++ 5.6 is a fairly old version at this point, and I believe more updates versions of g++ will handle that code with no problem.
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